disk_free_space
Beware of empty files!
<?php
// Wrong
$exp = floor(log($bytes) / log(1024));
//Correct
$exp = $bytes ? floor(log($bytes) / log(1024)) : 0;
?>
disk_total_space
(PHP 4 >= 4.1.0, PHP 5)
disk_total_space — Returns the total size of a directory
설명
float disk_total_space
( string $directory
)
Given a string containing a directory, this function will return the total number of bytes on the corresponding filesystem or disk partition.
인수
- directory
-
A directory of the filesystem or disk partition.
반환값
Returns the total number of bytes as a float.
예제
Example #1 disk_total_space() example
<?php
// $df contains the total number of bytes available on "/"
$df = disk_total_space("/");
// On Windows:
disk_total_space("C:");
disk_total_space("D:");
?>
주의
Note: 이 함수는 원격 파일을 다루지 못합니다. 파일은 서버 파일시스템을 통해서 사용 가능해야만 합니다.
add a note
User Contributed Notesdisk_total_space
Viitala
04-Feb-2008 06:04
04-Feb-2008 06:04
tularis at php dot net
25-Jun-2007 07:13
25-Jun-2007 07:13
For a non-looping way to add symbols to a number of bytes:
<?php
function getSymbolByQuantity($bytes) {
$symbols = array('B', 'KiB', 'MiB', 'GiB', 'TiB', 'PiB', 'EiB', 'ZiB', 'YiB');
$exp = floor(log($bytes)/log(1024));
return sprintf('%.2f '.$symbol[$exp], ($bytes/pow(1024, floor($exp))));
}
stierguy1 at msn dot com
25-Jun-2007 11:03
25-Jun-2007 11:03
function roundsize($size){
$i=0;
$iec = array("B", "Kb", "Mb", "Gb", "Tb");
while (($size/1024)>1) {
$size=$size/1024;
$i++;}
return(round($size,1)." ".$iec[$i]);}
nikolayku at tut dot by
18-Apr-2007 05:16
18-Apr-2007 05:16
Very simple function that convert bytes to kilobytes, megabytes ...
function ConvertBytes($number)
{
$len = strlen($number);
if($len < 4)
{
return sprintf("%d b", $number);
}
if($len >= 4 && $len <=6)
{
return sprintf("%0.2f Kb", $number/1024);
}
if($len >= 7 && $len <=9)
{
return sprintf("%0.2f Mb", $number/1024/1024);
}
return sprintf("%0.2f Gb", $number/1024/1024/1024);
}
Mat
05-Apr-2007 07:46
05-Apr-2007 07:46
JulieC:
I think you may have misunderstood - given a directory, this function tells you how big the disk paritition is that the directory exists on.
So disk_total_space("C:\Windows\") will tell you how big drive C is.
It is not suggesting that a directory is a disk partition.
JulieC
31-Jan-2007 12:11
31-Jan-2007 12:11
"filesystem or disk partition" does not equal "directory" for Windows. Thanks.
martijn at mo dot com
14-Jan-2007 07:41
14-Jan-2007 07:41
This works for me (on a UNIX server):
<?php
function du( $dir )
{
$res = `du -sk $dir`; // Unix command
preg_match( '/\d+/', $res, $KB ); // Parse result
$MB = round( $KB[0] / 1024, 1 ); // From kilobytes to megabytes
return $MB;
}
$dirSize = du('/path/to/dir/');
?>
shalless at rubix dot net dot au
16-Jul-2003 11:36
16-Jul-2003 11:36
My first contribution. Trouble is the sum of the byte sizes of the files in your directories is not equal to the amount of disk space consumed, as andudi points out. A 1-byte file occupies 4096 bytes of disk space if the block size is 4096. Couldn't understand why andudi did $s["blksize"]*$s["blocks"]/8. Could only be because $s["blocks"] counts the number of 512-byte disk blocks not the number of $s["blksize"] blocks, so it may as well just be $s["blocks"]*512. Furthermore none of the dirspace suggestions allow for the fact that directories are also files and that they also consume disk space. The following code dskspace addresses all these issues and can also be used to return the disk space consumed by a single non-directory file. It will return much larger numbers than you would have been seeing with any of the other suggestions but I think they are much more realistic:
<?php
function dskspace($dir)
{
$s = stat($dir);
$space = $s["blocks"]*512;
if (is_dir($dir))
{
$dh = opendir($dir);
while (($file = readdir($dh)) !== false)
if ($file != "." and $file != "..")
$space += dskspace($dir."/".$file);
closedir($dh);
}
return $space;
}
?>
andudi at gmx dot ch
12-Jun-2002 07:15
12-Jun-2002 07:15
To find the total size of a file/directory you have to differ two situations:
(on Linux/Unix based systems only!?)
you are interested:
1) in the total size of the files in the dir/subdirs
2) what place on the disk your dir/subdirs/files uses
- 1) and 2) normaly differs, depending on the size of the inodes
- mostly 2) is greater than 1) (in the order of any kB)
- filesize($file) gives 1)
- "du -ab $file" gives 2)
so you have to choose your situation!
on my server I have no rights to use "exec du" in the case of 2), so I use:
$s = stat($file);
$size = $s[11]*$s[12]/8);
whitch is counting the inodes [12] times the size of them in Bits [11]
hopes this helps to count the used disk place in a right way... :-)
Andreas Dick